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A body of mass 8.0 kg is traveling at 2.0 m/s under the influence of no external force. At a certain instant an internal explosion occurs, splitting the body into two chunks of 4.0 kg mass each; 16 J of translational kinetic energy are imparted to the two-chunk system by the explosion. Neither chunk leaves the line of the original motion. Determine the speed and direction of motion of each of the chunks after the explosion.
A body of mass 8.0 kg is traveling at 2.0 m/s under the influence of no external force. At a certain instant an internal explosion occurs, splitting the body into two chunks of 4.0 kg mass each; 16 J of translational kinetic energy are imparted to the two-chunk system by the explosion. Neither chunk leaves the line of the original motion. Determine the speed and direction of motion of each of the chunks after the explosion.

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5 years ago

Hasan Naqvi
97 Points
```							Original kinetic energy= 1/2mv2 =  16JEnergy imparted due to explosion = 16JTotal energy = 32J ½ m1v12 + 1/2 m2v22  = 32J2 v12 + 2v22 = 32Jv12 + v22 = 16J Also m1v1 + m2v2 = mv (conservation of linear momentum)4v1 + 4v2 = 8 x 2v1 + v2 = 4(v1 + v2 )2= 16i.e. v1v2 = 0 So one of the chunk stops at rest, while the other chunk moves with a velocity 4m/s in the same direction.
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5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions