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Grade: 9
`        A body of mass 40 kg stands on a weighing machine in a accelerated lift. The reading on the scale of the weighing machine is 300N. Find the magnitude and direction of acceleration. (g=9.8 m/s^2)`
2 years ago

## Answers : (1)

Arun
23781 Points
```							Dear student M=40kgF=300Nsuppose that g=9.8m/s²Now, when the lift goes down, 2 types of accelerations are applied, 1. gravitational acceleration2.acceleration of lifeBy thinking about the FBD of the lift,if the lift moves down, the sum of acceleration = g-aand if it moves up, it is g+a[why? Becuase when the life moves, an illusory acceleration is applied on it, which is 'a' here]That means, 1. if the lift is moving upwards,F=m(g+a)300=40(10+a)a= -2/5 m/s²2. if lift is going down,F=m(g-a)300=40(10-a)a= +2/5 m/s²Now the directions: 1.if the lift moves downwards, the magnitude of acceleration is +2/5 m/s²2.if the lift moves downwards, the magnitude of acceleration is -2/5 m/s² RegardsArun (askIITians forum expert)
```
2 years ago
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