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Grade: upto college level
         A body of mass 2 kg suspended through a vertical spring executes simple harmonic motion of period 4 s. If the oscillations are stopped and the body hangs in equilibrium, find the potential energy stored in the spring. 
5 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
							Sol. m = 2kg.
T = 4 sec.
T = 2π √(m/k) ⇒ 4 = 2π √(2/k) ⇒ 2 = π √(2/k)
⇒ 4 = π2 (2/k) ⇒ k = 2 π2/4 ⇒ k = π2/2 = 5 N/m
But, we know that F = mg = kx
⇒ x = mg/k = 2 x 10/5 = 4
∴Potential Energy = (1/2) k x2 = (1/2) × 5 × 16 = 5 × 8 = 40J

						
5 years ago
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