0

Guest

Courses New

A body of mass 2 kg suspended through a vertical spring executes simple harmonic motion of period 4 s. If the oscillations are stopped and the body hangs in equilibrium, find the potential energy stored in the spring.

A body of mass 2 kg suspended through a vertical spring executes simple harmonic motion of period 4 s. If the oscillations are stopped and the body hangs in equilibrium, find the potential energy stored in the spring.

Grade:upto college level

1 Answers

Deepak Patra
askIITians Faculty 471 Points
9 years ago
Sol. m = 2kg. T = 4 sec. T = 2π √(m/k) ⇒ 4 = 2π √(2/k) ⇒ 2 = π √(2/k) ⇒ 4 = π2 (2/k) ⇒ k = 2 π2/4 ⇒ k = π2/2 = 5 N/m But, we know that F = mg = kx ⇒ x = mg/k = 2 x 10/5 = 4 ∴Potential Energy = (1/2) k x2 = (1/2) × 5 × 16 = 5 × 8 = 40J

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More