A body of mass 2 kg is placed on rough surface of coefficient of friction 0.8 and a force of 10 N is applied on the body.the static frictional force acts on the body is

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Saurav · Answer

Maximum value of static friction is kmg K is friction coefficient=0.8 Now f max is 16 As force applied is less than f max it will be equal to applied force Therefore f applicable is 10N

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A body of mass 2 kg is placed on rough surface of coefficient of friction 0.8 and a force of 10 N is applied on the body.the static frictional force acts on the body is

A body of mass 2 kg is placed on rough surface of coefficient of friction 0.8 and a force of 10 N is applied on the body.the static frictional force acts on the body is

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A body of mass 2 kg is placed on rough surface of coefficient of friction 0.8 and a force of 10 N is applied on the body.the static frictional force acts on the body is

A body of mass 2 kg is placed on rough surface of coefficient of friction 0.8 and a force of 10 N is applied on the body.the static frictional force acts on the body is

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