a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration
muqaddas , 4 Years ago
Grade 12th pass
2 Answers
Arun
Last Activity: 4 Years ago
Dear student
w = sqrt(k/m) = 20
1/2 m w² A² = 1/10
Acceleration = A w² = 400/10 = 40
Hopw it helps
Thanks and regards
Vikas TU
Last Activity: 4 Years ago
Dear student
For more such examples nd concept please refer the link below