a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

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Arun · Answer

Dear student w = sqrt(k/m) = 20 1/2 m w² A² = 1/10 Acceleration = A w² = 400/10 = 40 Hopw it helps Thanks and regards

Vikas TU · Answer

Dear student For more such examples nd concept please refer the link below https://www.askiitians.com/iit-study-material/iit-jee-physics/oscillation/simple-harmonic-motion/ Good Luck

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a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

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a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

2 Answers

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