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a body of mass 1 kg is suspended from the free end of a spring having force constant 400n/m is executing s.h.m.when the total energy of the system is 2 joule,find the maximum acceleration

muqaddas , 4 Years ago
Grade 12th pass
anser 2 Answers
Arun

Last Activity: 4 Years ago

Dear student
 
w = sqrt(k/m) = 20
1/2 m w² A² = 1/10
 
 
 
Acceleration = A w² = 400/10 = 40
 
Hopw it helps
 
Thanks and regards

Vikas TU

Last Activity: 4 Years ago

Dear student 
For more such examples nd concept please refer the link below 
Good Luck 

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