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        A body of mass 1 kg breaks into three frames whose masses are in the ratio 1:1:3 fragments of equal masses move with speed of 30m/s in mutually perpendicular directions . The speed of heavier fragment will be.  PLASE TELL ME ANSWER IN FIGURE ALSO
one year ago

Khimraj
3008 Points
							As external force is zero.apply conservation of momentum0 = (1/5)*30$\hat{i}$ + (1/5)*30$\hat{j}$ + (3/5)*vso v = 10$\hat{i}$ + 10$\hat{j}$ = $10\sqrt{2} m/s$Hope it clears...........................

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions