A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?
testingforumsleads , 7 Years ago
Grade 12
1 Answers
Hemangi Vishe
Last Activity: 7 Years ago
by energy consrevation,
mgh = ½ mv2 + ½ kx2
10*10*60 = ½ 10*v2 + ½ 60*22
6000 = 5v2 + 120
5v2 =5880
v2 = 1176
v = 34.29
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