A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?

Question

Hemangi Vishe · Answer

by energy consrevation, mgh = ½ mv 2 + ½ kx 2 10*10*60 = ½ 10*v 2 + ½ 60*2 2 6000 = 5v 2 + 120 5v 2 =5880 v 2 = 1176 v = 34.29

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A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?

A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?

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A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?

A body of 10 kg weight drops from a height of 60 cm upon a spring whose modulus is 60 kg/cm . What will be the speed of the block when the spring is deformed 2 cm?

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