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A body is weighed by a spring balance to be 1.000 kg at the north pole. How much will it weigh at the equator? Account for the earth’s rotation only.
Sol. Let g’ be the acceleration due to gravity at equation & that of pole = g g’ = g ω^2 R = 9.81 – (7.3 * 10^-5)^2 * 6400 * 10^3 = 9.81 – 0.034 = 9.776 m/s^2 Mg’ = 1 kg * 9.776 m/s^2 = 9.776 N or 0.997 kg The body will weight 0.997 kg at equator
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