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A body is thrown vertically upwards from the top A of a tower. It reaches the ground in t1 sec. if it is thrown the vertical downwards from A with the same speed it reaches the ground in reach the ground.

chetan , 10 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

When a body is thrown vertically from a height, its motion is influenced by gravity, which accelerates it downwards. The scenario you described involves two different cases: throwing the object upwards and throwing it downwards. Let's break down what happens in each case and how the time taken to reach the ground differs.

Case 1: Thrown Vertically Upwards

When the object is thrown upwards, it first moves against the force of gravity. As it ascends, it slows down until it reaches its highest point, where its velocity becomes zero momentarily. After that, it begins to fall back down, accelerating due to gravity until it reaches the ground.

Time of Flight Calculation

The total time taken to reach the ground, denoted as t1, can be divided into two parts:

  • Time to reach the highest point (t_up)
  • Time to fall from the highest point to the ground (t_down)

Using the equations of motion, we can express these times in terms of the initial velocity (u) and the height (h) of the tower:

  • For the upward motion: v = u - gt (where v = 0 at the highest point)
  • For the downward motion: h = 0.5gt²

The total time t1 can be expressed as:

t1 = t_up + t_down

Case 2: Thrown Vertically Downwards

In this scenario, when the object is thrown downwards with the same initial speed, it immediately starts moving towards the ground, and gravity assists its motion from the start. This means it will reach the ground faster than in the first case.

Time of Flight Calculation

For the downward throw, the time taken to reach the ground, denoted as t2, can be calculated using the same principles:

  • The object is already moving downwards with an initial velocity (u).
  • The time taken to reach the ground can be calculated using the equation of motion:

h = ut + 0.5gt²

In this case, the total time t2 will be less than t1 because the object does not spend time moving upwards before falling.

Relationship Between t1 and t2

From the analysis, we can conclude that:

    t1 is the time taken when the object is thrown upwards, reaches a maximum height, and then falls back down. t2 is the time taken when the object is thrown downwards, starting its descent immediately.

Since the object thrown downwards has the advantage of starting its fall with an initial velocity, it will reach the ground in a shorter time. Thus, we can say:

t2 < t1

In summary, the time taken for the object to reach the ground differs based on the direction of the throw due to the effects of gravity and the initial velocity imparted to the object. This illustrates the fundamental principles of kinematics and the influence of gravitational acceleration on motion. If you have any further questions or need clarification on any part of this explanation, feel free to ask!

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