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A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

```
8 months ago

Arun
25768 Points
```							Dear student Maximum height = u² sin²theta/2g = u² /2g Niw maximum R =u² /g Hence maximum height = R/2
```
8 months ago
Vikas TU
14146 Points
```							Dear student Above ans is incorrect Applying conservation of mechanical energy 1/2 mu^2 - GMm/R = - GMm/(R+h)Solving this R+h = 2gR^2 /(2gR -u^2)h = 2gR^2 /(2gR-u^2) - R h = u^2/(gR-u^2)Good Luck
```
8 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions