A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

Question

Arun · Answer

Dear student Maximum height = u² sin²theta/2g = u² /2g Niw maximum R =u² /g Hence maximum height = R/2

Vikas TU · Answer

Dear student Above ans is incorrect Applying conservation of mechanical energy 1/2 mu^2 - GMm/R = - GMm/(R+h) Solving this R+h = 2gR^2 /(2gR -u^2) h = 2gR^2 /(2gR-u^2) - R h = u^2/(gR-u^2) Good Luck

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A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

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A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

A body is thrown from the surface of the earth with a velocity of u m/s. The maximum height in meters reached by it will be ? (Answer should be in terms of R ,u ,g where R is radius of earth and,g is acceleration due to gravity)

2 Answers

Think You Can Provide A Better Answer ?

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