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Mechanics

A body is projected with a velocity of 40 m per second. After 2 seconds it crosses a vertical pole of length 20.4 metre. calculate the angle of projection and the distance of ball that will hits the Ground from the pole.

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8 Years agoGrade
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Profile image of Arun
8 Years ago
Dear student

U = 40 m/s     g = 9.8 m/s
At   t1 = 2 sec    y = 20.4 m
y = u sin?  t  - g t² /2
20.4 = 40 sin? * 2 - g 2² /2
=>  sin? = 1/2
=>  ? = 30°
Horizontal range = R = u² Sin2? / g = 40² sin60° / 9.8  = 141.39 m
 
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Arun (askIITians forum expert)