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a body is projected vertically upward such that it crossed a point at t=2s and again at t=8s from point of projectionthe height of the tower is

Anush Bedkyale , 4 Years ago
Grade 10
anser 1 Answers
Vikas TU

Last Activity: 4 Years ago

Let the desired velocity be u 
As the particle returns to the same point in (8-2) that is 6 second 
Its displacement in 6 sec = 0 
s = ut+0.5 at^2 
0= u (6) - 0.5 *10*36 
u = 30 m/s 
v^2 - u^2 = -2gh 
900 = 2gh
h = 45m

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