a body is projected vertically upward such that it crossed a point at t=2s and again at t=8s from point of projectionthe height of the tower is
Anush Bedkyale , 4 Years ago
Grade 10
1 Answers
Vikas TU
Last Activity: 4 Years ago
Let the desired velocity be u As the particle returns to the same point in (8-2) that is 6 second Its displacement in 6 sec = 0 s = ut+0.5 at^2 0= u (6) - 0.5 *10*36 u = 30 m/s v^2 - u^2 = -2gh 900 = 2gh h = 45m
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