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A body is projected vertically up at t=0 with a velocity of 98m/s .Another body is projected from the same point with same velocity after 4 seconds .Both bodies will meet at time=?
The answer is incomplete ,the second body projected after 4 seconds so we need to add 4 s. So the answer will be 4+8=12
Both the bodies will meet after 12 seconds.Solution:As the initial velocity at which the bodies A and B projected are same and also the position pf meeting will also be same so The height covered by the projecting body is The time taken to reach the point H for object A is tThe time taken to reach the point H for object B is (t-4) as the object B is thrown after 4s of throwing A. So, As u = 98 m/s , the above equation will become as Thus, it will take 12 s by object B to join object A.
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