Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A body is projected vertically from the earth`s surface with velocity equal to half of the escape velocity.what is maximum height reached by the body?
From conservation of mechanical energy(1/2)* m(Ve/2)^2 = mgh/[1+(h/r)]As Ve = (2gR), where R = radius of earthHence(1/2)*m.(2gR/2)^2 = m*g *h*R /(h+R)On solving h = R/3
from law of conservation of energy (1/2)mv^2 = mgh (1/2)v^2 = gh h = (1/2g)v^2 putting v= (under root 2gr)/2 h= 2gr/4×2g h= r/4 h= (radius of earth)/4
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -