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A body is projected vertically from the earth`s surface with velocity equal to half of the escape velocity.what is maximum height reached by the body? A body is projected vertically from the earth`s surface with velocity equal to half of the escape velocity.what is maximum height reached by the body?
From conservation of mechanical energy(1/2)* m(Ve/2)^2 = mgh/[1+(h/r)]As Ve = (2gR), where R = radius of earthHence(1/2)*m.(2gR/2)^2 = m*g *h*R /(h+R)On solving h = R/3
from law of conservation of energy (1/2)mv^2 = mgh (1/2)v^2 = gh h = (1/2g)v^2 putting v= (under root 2gr)/2 h= 2gr/4×2g h= r/4 h= (radius of earth)/4
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