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A body is projected vertically from the earths surface with velocity equal to half of the escape velocity.what is maximum height reached by the body?
A body is projected vertically from the earths surface with velocity equal to half of the escape velocity.what is maximum height reached by the body?


3 years ago

Arun
25768 Points
							From conservation of mechanical energy(1/2)* m(Ve/2)^2 = mgh/[1+(h/r)]As Ve = $\sqrt$(2gR), where R = radius of earthHence(1/2)*m.($\sqrt$2gR/2)^2 = m*g *h*R /(h+R)On solving h = R/3

3 years ago
Vikram
13 Points
							from law of conservation of energy  (1/2)mv^2 = mgh   (1/2)v^2 = gh   h = (1/2g)v^2  putting v= (under root 2gr)/2   h=  2gr/4×2g   h= r/4  h= (radius of earth)/4

2 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions