Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A body is projected downwards at an angle 30degrees to the horizontal with a velocity 9.8m/s from the top of a 29.4 m high tower. Its horizontal distance on the ground from the tower is 1)9.8 2)9.3√3 3)4.9`
7 months ago

## Answers : (1)

Arun
12304 Points
```							initial vertical velocity= usin30 = 4.9m/svertical distance traversed= 29.4mSo,h = ut + 1/2gt229.4=4.9*t +4.9t2on solving we gett2 + t – 6 = 0 (on solving quadratic equation)t = 3 seconds.Now you can also solve for distance. RegardsArun (askIITians forum expert)
```
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

## COUPON CODE: SELF10

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions