A body is projected downwards at an angle 30degrees to the horizontal with a velocity 9.8m/s from the top of a 29.4 m high tower. Its horizontal distance on the ground from the tower is 1)9.8 2)9.3√3 3)4.9
Geetha , 6 Years ago
Grade 12
1 Answers
Arun
Last Activity: 6 Years ago
initial vertical velocity= usin30 = 4.9m/s vertical distance traversed= 29.4m So, h = ut + 1/2gt2 29.4=4.9*t +4.9t2 on solving we get t2 + t – 6 = 0 (on solving quadratic equation) t = 3 seconds. Now you can also solve for distance.
Regards Arun (askIITians forum expert)
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