A body is projected at an angle of 60° with the horizontal ground with kinetic energy k. When the velocity makes an angle 30° wIth the horizontal, the kinetic energy of the body will be what?

Question

Bejoi Mathew · Answer

H=

Bejoi Mathew · Answer

H=u 2 sin 2 x/2g u 2 =H * 2g/sin 2 x BUT, KINETIC ENERGY ∝ u 2 ∝ 1/ sin 2 x Solve you will get. Hope this helps. Best of luck.

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A body is projected at an angle of 60° with the horizontal ground with kinetic energy k. When the velocity makes an angle 30° wIth the horizontal, the kinetic energy of the body will be what?

A body is projected at an angle of 60° with the horizontal ground with kinetic energy k. When the velocity makes an angle 30° wIth the horizontal, the kinetic energy of the body will be what?

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A body is projected at an angle of 60° with the horizontal ground with kinetic energy k. When the velocity makes an angle 30° wIth the horizontal, the kinetic energy of the body will be what?

A body is projected at an angle of 60° with the horizontal ground with kinetic energy k. When the velocity makes an angle 30° wIth the horizontal, the kinetic energy of the body will be what?

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

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