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`        A body is projected at an angle 45 degrees with the horizontal with velocity 40 root2 m/s. Its resulatant displacement after 2secs isa.80m b.100m c.640m d.60m`
2 years ago

763 Points
```							We can calculate it by finding horizontal and vertical displacement of particles .Horizontal and vertical component of velocity is equal to 40m/s.Vertical Displacement of particle after 2 second = 40.2-1/2.10.2.2=60mHorizontal displacement of particle after 2 second = 40.2-0= 80mNow net displacement of particle = √ (80)^2 + (60)^2 = 100m.Hence (b) is the correct option.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions