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Grade: 12th pass

                        

A body is moved along a straight line by a machine delivering a constant power. The distance moved by the body in time ‘t’ is proportional to a) t 3/4 b) t 3/2 c) t 1/4 d) t 1/2

6 years ago

Answers : (6)

Vasantha Kumari
askIITians Faculty
38 Points
							
181-1113_displacement_solution.jpg
6 years ago
kansal123
11 Points
							
sir how can we use s=0.5at^2. it is used only when acceleration is constant. Here we cant say that as force can be changing with time so does acceleration
4 years ago
Adithya PV
13 Points
							Force has a constant value.                     So acceleration is also constant.....                       So we can use it in that case.
						
3 years ago
NIRAV
12 Points
							
POWER = WORK DONE/ TIME = CHANGE IN KINETIC ENERGY PER TIME
= ½*M*V2/T  =  ½*M* (S/T)2/T 
= ½*M*S2/T3
S2=CONSTANT* T3
HENCE S IS PROPOTIONAL TO T3/2.
3 years ago
mega thilagaa
21 Points
							Power=f.v             =ma.v                =m(v/t).(S/t)                 =m/t×s/t×s/t.      {P=constant}                    1=m{s^2/t^3}                    S^2=t^3                      S=t^3/2Hence derivedThis is the simplest way I got the ans
						
2 years ago
Yash Chourasiya
askIITians Faculty
246 Points
							Dear Student

Let's consider a body is moved along a straight line by a machine delivering a constant powerP. The distance moved by the body isS.
Power,P = F.v.. . . . . . (1)
Force,F = ma. . . . . . . .(2)

where,v = S/t​
acceleration,a = S/t2
m =mass
From equation (1) and equation (2), we get
S2= Pt3/m​

From the above equation, we get
S2 ∝ t3
S ∝ t3/2
So option (B) is correct.

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
4 months ago
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