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a body is dropped from a height of 16 mthe body strikes the ground and lossess 25% velocitythe body rebounds to a height of

harika , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
at first when the body is dropped, u=0, remove voyaged is 16m in this manner last speed before hitting the ground is 
v2=u2+ 2as 
v2= 2x gx 16. 
since 25% dynamic vitality is lost in impact, the vitality left in the body is 75% 
in this manner 75/100 x 1/2mv2= mgh 
where h is the separation to which it bounce back.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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