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Grade 11Mechanics

a body is dropped from a height of 16 m the body strikes the ground and lossess 25% velocity the body rebounds to a height of

Profile image of harika
9 Years agoGrade 11
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1 Answer

Profile image of Vikas TU
9 Years ago
Dear Student,
at first when the body is dropped, u=0, remove voyaged is 16m in this manner last speed before hitting the ground is 
v2=u2+ 2as 
v2= 2x gx 16. 
since 25% dynamic vitality is lost in impact, the vitality left in the body is 75% 
in this manner 75/100 x 1/2mv2= mgh 
where h is the separation to which it bounce back.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)