A body is dropped from a height of 16 m The body strikes the ground and looses 25% of its velocity. The body rebounds to a height of ........
Sreenidhi Varadi , 8 Years ago
Grade 11
2 Answers
abhi
Last Activity: 8 Years ago
Let v be the velocity when it strikes the ground .ie final velocity ,then v2-02=2*16*10=320,after rebound velocity V=3/4v,hight attained h=V2/2*10=(3/4)2*320/20=9/16*16=9m
When particle is dropped it will reached at ground with velocity √2gh OK.then it will rebounded with same velocity but of lose of energy it`s velocity becomes 0.75√2gh then after rebounded it`s final velocity and calculated height is 1.5 times of h.
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