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A body intially at rest breaks into two pieces having mass 2M and 3M respectively together having total kinetic emergy E . the piece of mass 2M after having kinetic energy
let speed of 2m,3m piece be u,v respectivelyby conservation of momentum2mu=3mvu=3v/2E=1/2 (2m)u^2 + 1/2 (3m)v^2put u=3v/2E=9/4mv^2+3/2mv^2E=15/4mv^2ke of 2kg block = 1 /2 (2m)u^2=9/4mv^2=9(E/15)=3E/5
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