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A body has an initial velocity of 88m/sec moving with an acceleration retardation of 2 m/ sec2 find the time after which it will stop and the distance it will travel before coming at rest
Given: u = 88m/sa = -2m/s2 , v = 0m/sV2-u2=2as02 - 882 = (2)(-2)s: s = 1936mAnd v = u + at 0 = 88 + (-2)t t = 44s
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