Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?
5m/s
we will solve this problem in two direction on in is horizontal and one in vertical.....in horizontal velocity will unchanged after 4 sec i.e Vx = 3 m/sin vertical motion intial velocity is zero and so final velocity in vertical motionVv = uy+at Vy = 0+1*4 = 4 m/s since acceleration is normal to the initial velocityso net velocity after 4 sec = v' = (4^2+3^2)^1/2 = 5 m/sdirection theta = tan inverse (vy/vx) = tan inverse (4/3)Thanks & Regards,Nirmal SinghAskiitians faculty
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -