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a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?

a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?

Grade:12th pass

2 Answers

Basanta Goswami
22 Points
10 years ago
5m/s
Nirmal Singh.
askIITians Faculty 44 Points
10 years ago
we will solve this problem in two direction on in is horizontal and one in vertical.....
in horizontal velocity will unchanged after 4 sec i.e Vx = 3 m/s
in vertical motion intial velocity is zero and so final velocity in vertical motion
Vv = uy+at
Vy = 0+1*4 = 4 m/s since acceleration is normal to the initial velocity
so net velocity after 4 sec = v' = (4^2+3^2)^1/2 = 5 m/s
direction theta = tan inverse (vy/vx) = tan inverse (4/3)
Thanks & Regards,
Nirmal Singh
Askiitians faculty

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