Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 12th pass


a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?

6 years ago

Answers : (2)

Basanta Goswami
22 Points
6 years ago
Nirmal Singh.
askIITians Faculty
44 Points
							we will solve this problem in two direction on in is horizontal and one in vertical.....
in horizontal velocity will unchanged after 4 sec i.e Vx = 3 m/s
in vertical motion intial velocity is zero and so final velocity in vertical motion
Vv = uy+at
Vy = 0+1*4 = 4 m/s since acceleration is normal to the initial velocity
so net velocity after 4 sec = v' = (4^2+3^2)^1/2 = 5 m/s
direction theta = tan inverse (vy/vx) = tan inverse (4/3)
Thanks & Regards,
Nirmal Singh
Askiitians faculty
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution

Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details