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a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ? a body has an initial velocity of 3m/s and has an acceleration of 1m/s^2 direction normal to the of initial velocity. The velocity of the body after 4 sec ?
5m/s
we will solve this problem in two direction on in is horizontal and one in vertical.....in horizontal velocity will unchanged after 4 sec i.e Vx = 3 m/sin vertical motion intial velocity is zero and so final velocity in vertical motionVv = uy+at Vy = 0+1*4 = 4 m/s since acceleration is normal to the initial velocityso net velocity after 4 sec = v' = (4^2+3^2)^1/2 = 5 m/sdirection theta = tan inverse (vy/vx) = tan inverse (4/3)Thanks & Regards,Nirmal SinghAskiitians faculty
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