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A body falling from the rest has a velocity v after it falls through a height h. The distance it has down further fir its velocity to become double ,will be

A body falling from the rest has a velocity v after it falls through a height h. The distance it has down further fir its velocity to become double ,will be

Grade:12th pass

1 Answers

Arun
25750 Points
6 years ago
Dear Deepak
 
Use
v^2 – u^2 = 2*g*s
intial velocity u=0
at velocity=v height=h
therefore
u^2 = 2gh
then let intial velocity u=v
and final velocity=2v
therefore
(2v)^2 – v^2 = 2*g*s
4* v^2 – v^2 = 3 v^2 = 6*g*h = 2g* (3h)

the distance it has to fall down further for its velocity to become 2v is 3.times h. 
 
 
Regards
Arun (askIITians forum expert)

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