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A body falling from a vertical hieght of 10m pierces through a distance of 1m in sand . It faces an average retardation in sand equal to (g = acceleration due to gravity) (a) g (b) 9g(c) 100g(d) 1000g

Khushboo , 6 Years ago
Grade 11
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

velocity of ball = \sqrt{2gh} = \sqrt{180}
then apply third equation of motion
0 = 180 – 2*a*1
so a = 90 = 9g
Hope it clears
                                                                                                                                                                                                                                                                                        

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