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Grade 12th passMechanics

a body falling from a high minaret travels 40 meter in the last 2 sec of its fall to ground height of minaret in meter

Profile image of pankaj yadav
7 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
7 Years ago
This problem can easily be solved with the help of equation of motion.
s = ut + 1/2 at^2
40 = 2u + 1/2.10.(2)^2
40 = 2u + 20
2u = 20
u = 10 m /s
Now,
v^2-u^2 = 2as
2.10.s=100
s = 5m
Hence the total distance traveled is 45M.