0

Guest

Courses New

a body falling from a high minaret travels 40 meter in the last 2 sec of its fall to ground height of minaret in meter

a body falling from a high minaret travels 40 meter in the last 2 sec of its fall to ground height of minaret in meter
 

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
This problem can easily be solved with the help of equation of motion.
s = ut + 1/2 at^2
40 = 2u + 1/2.10.(2)^2
40 = 2u + 20
2u = 20
u = 10 m /s
Now,
v^2-u^2 = 2as
2.10.s=100
s = 5m
Hence the total distance traveled is 45M.

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More