Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        A body covered a distance of 5 km along a semicircular path. The ratio of distance to displacement is
2 years ago

Arun
23487 Points
							Dear Ankit

Distance travelled = 2$\pi$*r/2 = $\pi$*r
But displacement = shortest distance between end point and starting point. = 2r
Hence ratio of distance to displacement = $\pi$*r/2*r = $\pi$/2
= 22/7*2 = 11/7

Regards

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions