A body at rest explodes into 2 pieces of masses m1and m2. Show that the ratio of their kinetic energies t1÷t2=m2÷m1

Question

Pranav Jayant Chiddarwar · Answer

As no external force is acting on the body wecan conserve momentum. m1v1=m2v2=P t 1 =1/2 m 1 v 1 2 = P 2 /2m 1 t 2 =1/2m 2 v 2 2 = P 2 /2m 2 therefore, t 1 /t 2 = m 2 /m 1

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A body at rest explodes into 2 pieces of masses m1and m2. Show that the ratio of their kinetic energies t1÷t2=m2÷m1

A body at rest explodes into 2 pieces of masses m1and m2. Show that the ratio of their kinetic energies t1÷t2=m2÷m1

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A body at rest explodes into 2 pieces of masses m1and m2. Show that the ratio of their kinetic energies t1÷t2=m2÷m1

A body at rest explodes into 2 pieces of masses m1and m2. Show that the ratio of their kinetic energies t1÷t2=m2÷m1

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