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```
A BOAT IS MOVING WITH VELOCITY 30 M/S TOWARDS EAST. AFTER 10S ITS VELOCITY BECOMES 40M/S TOWARDS NORTH. THE AVERAGE ACCELERATION OF THE BODY IS
A BOAT IS MOVING WITH VELOCITY 30 M/S TOWARDS EAST. AFTER 10S ITS VELOCITY BECOMES 40M/S TOWARDS NORTH. THE AVERAGE ACCELERATION OF THE BODY IS

```
3 years ago

Shailendra Kumar Sharma
188 Points
```							Assume average acceleration concept = (V2-V1)/time=(40j-30i)/10=4j-3iSo magnitude of acceleration is 5
```
3 years ago
Arun
25768 Points
```							Tr
```
3 years ago
Arun
25768 Points
```							Initial velocity = The velocity in east direction = 30i , where i is unit vector along x axis.Final velocity = The velocity in north direction = 40j , where j is unit vector along y axis. Average acceleration = { (root over(302+402))/10} m/s2                                = 5 m/s2 in north east direction!
```
3 years ago
Lakshay Kumar
43 Points
```							Initial velocity, u=30iFinal velocity, v=40jNow apply v=u+at40j=30i+a(10)10a=40j-30ia=4j-3i=>a=5m/s^2 in North-west direction
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions