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A BOAT IS MOVING WITH VELOCITY 30 M/S TOWARDS EAST. AFTER 10S ITS VELOCITY BECOMES 40M/S TOWARDS NORTH. THE AVERAGE ACCELERATION OF THE BODY IS

Priyanshu kansal , 7 Years ago
Grade 11
anser 4 Answers
Shailendra Kumar Sharma

Last Activity: 7 Years ago

Assume average acceleration concept = (V2-V1)/time=(40j-30i)/10=4j-3iSo magnitude of acceleration is 5

Arun

Last Activity: 7 Years ago

Tr

Arun

Last Activity: 7 Years ago

Initial velocity = The velocity in east direction = 30i , where i is unit vector along x axis.

Final velocity = The velocity in north direction = 40j , where j is unit vector along y axis. 
Average acceleration = { (root over(302+402))/10} m/s2 
                               = 5 m/s2 in north east direction! 

Lakshay Kumar

Last Activity: 7 Years ago

Initial velocity, u=30iFinal velocity, v=40jNow apply v=u+at40j=30i+a(10)10a=40j-30ia=4j-3i=>a=5m/s^2 in North-west direction

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