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A blockI of mass M is pulled along a horizontal surface by a rope of mass m . If force F applied one end of the rope,the force which the rope exerts on block is:a: FM/M+mb:Fm/m+Mc:FM/M-md:Fm/M-m

Vipul Kumar , 9 Years ago
Grade 11
anser 1 Answers
Neeti

Last Activity: 9 Years ago

Since F causes motion of M and m, F = (M+m) a
 so accelaration is F /M+m
 
Now for the small mass m, force applied by rope = T =  m x a
 
= (F/M+m) x m = Fm/m+M = option b. 
 
Please feel free to ask any follow up question and approve the answer if you like it :)

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