A block with mass m is supported by cord C from the ceiling, and a similar cord D is attached to the bottom of the block (Fig. 3-21). Explain this: If you give a sudden jerk to D, it will break, but if you pull on D steadily, C will break.

Question

Aditi Chauhan · Answer

As you sudden jerk to D, the time of impact of force acting on the block is less. So the tension exerted on the block due to the down ward external force exerted by the cord D will be less. Thus, in this case less energy will transfer to the chord C. Therefore if you give a sudden jerk to D, it will break. But if you pull on D steadily, the time of impact of force acting on the block is more. So the tension exerted on the block due to the down ward external force exerted by the cord D will be more. Thus more energy will be transfer to the cord C. Therefore if you pull on D steadily, C will break.

harshay dharade · Answer

if u sudden jerk to D --C will break as it as load of loaded body + given force , and C cord has only given force thats why. if u stedy jerk to D in this case also C cord break 1 st and then also chance of breaking of cord D.

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A block with mass m is supported by cord C from the ceiling, and a similar cord D is attached to the bottom of the block (Fig. 3-21). Explain this: If you give a sudden jerk to D, it will break, but if you pull on D steadily, C will break.

A block with mass m is supported by cord C from the ceiling, and a similar cord D is attached to the bottom of the block (Fig. 3-21). Explain this: If you give a sudden jerk to D, it will break, but if you pull on D steadily, C will break.

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A block with mass m is supported by cord C from the ceiling, and a similar cord D is attached to the bottom of the block (Fig. 3-21). Explain this: If you give a sudden jerk to D, it will break, but if you pull on D steadily, C will break.

A block with mass m is supported by cord C from the ceiling, and a similar cord D is attached to the bottom of the block (Fig. 3-21). Explain this: If you give a sudden jerk to D, it will break, but if you pull on D steadily, C will break.

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