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A block released from rest from the top of a smooth inclined plane of inclination 45 takes time t to reach the bottom. The same block released from rest from top of a rough inclined plane of the same inclination takes time 2t to reach the botttom. The coefficient of friction is : a)0.75(answer), b)0.5, c)0.25, d)0.4, e)0.33, How do you get this answer?
A block released from rest from the top of a smooth inclined plane of inclination 45 takes time t to reach the bottom. The same block released from rest from top of a rough inclined plane of the same inclination takes time 2t to reach the botttom. The coefficient of friction is :a)0.75(answer), b)0.5, c)0.25, d)0.4, e)0.33, How do you get this answer?

```
4 years ago

nikita chaubey
44 Points
```							Coefficient of friction is given by tan theta (n*n-1/n*n) on putting the value we get  tan 45°[ 4-1/4]  = 3/4 0.75
```
4 years ago
Grace Mathew
10 Points
```							Can I ask you why the coefficient of friction is tan theta((n*n-1)/n*n)? Thanks for the answer :) !!!
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions