badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass

                        

A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

4 years ago

Answers : (2)

Vikas TU
12280 Points
							
In parallel direction the force he would required => mgsin37 = > 100*3/5 => 300/5 => 60N.
Work done => 60 * 2 = 120 Joule.
 
In horizontal direction, the force would be => mgcos37 => 100*4/5 => 400/5 => 80 N.
4 years ago
srinivas
11 Points
							
the amount of work done would be same in both the cases, as work done is same in all cases i.e., even if it is lifted by same amount of vertical displacement.
m g h = m g l sin37° =120J
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details