A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

Question

Vikas TU · Answer

In parallel direction the force he would required => mgsin37 = > 100*3/5 => 300/5 => 60N. Work done => 60 * 2 = 120 Joule. In horizontal direction, the force would be => mgcos37 => 100*4/5 => 400/5 => 80 N.

srinivas · Answer

the amount of work done would be same in both the cases, as work done is same in all cases i.e., even if it is lifted by same amount of vertical displacement. m g h = m g l sin 37° =120J

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A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

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A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

A block of weight 100N is slowly slid up on the smooth incline of inclination 37° by person. Calculate the work done by the person in moving the block through a distance of 2.0 m if mass he driving force is (a) parallel to incline and (b) in horizontal direction .

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