Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree
Given angle of friction =30Coefficient of friction u=tan30=1/√3Let min force is FNormal reaction N=20+Fsin60To just move the blockFcos60=uNF=20N
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -