A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree

Question

Himanshu Rathour · Answer

Given angle of friction =30 Coefficient of friction u=tan30=1/√3 Let min force is F Normal reaction N=20+Fsin60 To just move the block Fcos60=uN F=20N

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A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree

A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree

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A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree

A block of rate 20 newton is on a horizontal surface minimum force applied to pull it when applied force makes an angle 60 degree with horizontal angle of friction a is equal to 30 degree

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