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A block of material has density p1 and floats three-fourth submerged in a liquid of density p2,then p2=n/3×p1 tyen n=?

A block of material has density p1 and floats three-fourth submerged in a liquid of density p2,then p2=n/3×p1 tyen n=?

Grade:11

1 Answers

Arun
25750 Points
5 years ago

The fraction of volume of floating body immersed in a liquid is equal to its relative density w.r.t that liquid.

Since the body floats with 1/3 volume outside water 2/3 volume is immersed inside water. So its density is (2/3)d. Where d is density of water.

As the body floats with 3/4 volume outside liquid, the volume immersed in liquid is 1/4. So its density is (1/4)d'.

d'/4 = 2d/3

= d' = 8d/3

Given density if water is 1g/cc, density if the liquid is 8/3 g/cc.

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