Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A block of mass M with semicircular track of radius R ,rests on a horizontal frictionless surface.A uniform cyllinder of radius r and mass m is released at the top (pont A)The cyllinder slips on the semicircular frictionless track.How far has the block moved when the cyllinder reaches the bottom (point B)of the track?[Ans :-m(R-r)/(M+m)] How fast is the block moving when the cyllinder reaches the bottom of the track?

A block of mass M with semicircular track of radius R ,rests on a horizontal frictionless surface.A uniform cyllinder of radius r and mass m is released at the top (pont A)The cyllinder slips on the semicircular frictionless track.How far has the block moved when the cyllinder reaches the bottom (point B)of the track?[Ans :-m(R-r)/(M+m)] How fast is the block moving when the cyllinder reaches the bottom of the track?

Grade:11

1 Answers

Archit Uttarwar
35 Points
2 years ago
Here external force is 0 therefore,
Let x be the displacement of the wedge, 
And r is the radius of cylinder and R is radius of semicircular path
0= m(R-r-x) - Mx
x(M+m) =m(R-r)
x=m(R-r)/(M+m) 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free