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a block of mass M is released on the top of a smooth inclined plane of length X and inclination theta as shown in figure horizontal surface is rough if block comes to rest after moving a distance d on the horizontal surface then coefficient of friction between block and the surface is
Mechanical energy is conservedu=0, v=0mgh-(M)mgd=Kf - Ki =(1/2)mv² -(1/2)mu² =0So, mgh=Mmgd M=h/d...... But, we know that h=xsin(theta)Thus, M=xsin(theta)/dWhere, M=co-efficient of friction
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