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Grade: 12th pass

                        

a block of mass M is released on the top of a smooth inclined plane of length X and inclination theta as shown in figure horizontal surface is rough if block comes to rest after moving a distance d on the horizontal surface then coefficient of friction between block and the surface is

3 years ago

Answers : (1)

Deepshikha
16 Points
							
Mechanical energy is conserved
u=0, v=0
mgh-(M)mgd=K- Ki
             =(1/2)mv² -(1/2)mu²
              =0
So, mgh=Mmgd
       M=h/d......         But, we know that h=xsin(theta)
Thus, M=xsin(theta)/d
Where, M=co-efficient of friction
  1.  
2 years ago
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