×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A block of mass M is pulled along a horizontal smooth surface by a rope of mass m. force P is applied at one end of the rope. The force which the rope exert on the block is
A block of mass M is pulled along a horizontal smooth surface by a rope of mass m. force P is applied at one end of the rope. The force which the rope exert on the block is

```
3 years ago

John Sharon Sandeep
41 Points
```							Since F=ma, a=F/m.  Therefore acceleration of the things=P/(M+m).Now force exerted on the object of mass M= ma =M×P/(M+m)=MP/(M+m).☺In the above step i have to find acceleration of the system in terms of only P,m,M as acc. is not given any specif
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions