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1. a block of mass m = 5kg is resting on a rough horizontal surface for which the cofficient of friction 0.2 . when a force of 40N is applied as shown in the figure the acceleration of the blocks will be :
4 months ago

Arun
23386 Points

Dear student

There is no image attached . Please check and repost the question with an attachment.
4 months ago
Vikas TU
9810 Points

Mass of block = 5kg
F = 40N
μ = 0.2
g = 10 m/s²
friction, f = μmg = 0.2×5×10 = 10N
net force =F-f = 40-10 = 30N
acceleration = 30/5 = 6m/s²
4 months ago
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