a block of mass .50 kgs is moving with speed of 2 ms on smooth surface. it strikes with another mass of 1 kg then they move together as single body.The energy losss during collision is
priyabishnoi , 8 Years ago
Grade 11
1 Answers
Mayukh Chakrabarty
Last Activity: 8 Years ago
m=0.5 kg , u=2 m/sM=0.5+1=1.5 kgBy conservation of momentum,v=(mu)/M = 2/3Initial Kinetic Energy = (m * u^2)/2= 1Final Kinetic Energy = (M * v^2)/2 = 1/3So , loss = 2/3All data are in SI units .
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free