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Grade 12th passMechanics

A block of mass 2kg rests on the inclined plane making an angel of 30 degree with the horizontal. If the kinetic frictional coefficient is 0.6, what is the frictional force on the block

Profile image of AKOJU SAI KUMAR
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
8 Years ago
Given, m = 2 kg
θ = 300
μ = 0.6

R = m g cos ​θ
Therefore, force of friction, F = ​μ R = ​μ m g cos ​θ = 0.6 X 2 X 9.8 X cos 300 = 10.16 N
 
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Arun (askIITians forum expert)