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Grade 12Mechanics

A block of mass 2Kg is sliding with a constant velocity 8 m/s on a frictionless horizontal surface. The force exerted on the horizontal surface is nearly

Profile image of U Shruthi
10 Years agoGrade 12
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3 Answers

Profile image of Saurabh Kumar
10 Years ago
Force exerted on the horizontal surface is the weight of the block = mg = 20 N
Profile image of Tejas Pathak
9 Years ago
According to the Newton’s law of inertia (Newton’s First Law of Motion) the body can move with a constant speed only if it is acted upon by the balanced forces.In this question as the body of 2 kg is sliding with a constant velocity the gravitational pull of the earth on it is balanced by the opposing force (friction). So the force balancing the gravitational pull of the earth is equal to its weight = 2 ⨯9.8 N = 19.6 N
Profile image of King
7 Years ago
According to Newton's law of inertia we can take a =10m/s and m=2 kg putting in the formula f=ma,2×10 20N