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Grade: 12th pass
        
A block of mass 20kg is balance by three strings A,B & C as shown in the figure.Ratio of string A and B(TA/TB) is??
4 months ago

Answers : (2)

Arun
22533 Points
							
Dear student
 
Use Laami’s theorem
 
Ta / sin 150 = Tb / sin 127 = 20g / sin 83
 
Now you can solve.
 
Regards
Arun
4 months ago
Pooja
124 Points
							
Tension in string A and B be TA and TB respectively.
Angle between the horizontal line and vertical line of string A are 37° and 57° respectively.
 
Angle between the horizontal line and vertical line of string B are 60°and 30°respectively.

Taking components of force and balancing them we get 
TA sin37 +TB sin60 = 20g
TA cos37 = TB cos60
So TA/TB  =  cos60/cos37
                   =  (3)1/2/2  ÷ 4/5 
 
                   = 5(3)1/2 / 8
Answer us b
 
 
4 months ago
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