Pooja
Last Activity: 5 Years ago
Tension in string A and B be TA and TB respectively.
Angle between the horizontal line and vertical line of string A are 37° and 57° respectively.
Angle between the horizontal line and vertical line of string B are 60°and 30°respectively.
Taking components of force and balancing them we get
TA sin37 +TB sin60 = 20g
TA cos37 = TB cos60
So TA/TB = cos60/cos37
= (3)1/2/2 ÷ 4/5
= 5(3)1/2 / 8
Answer us b