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a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?
friction force= 4NAPPLIED FORCE= 10 NNET FORCE= 10N-4N= 6Nacceleration of block= 6N/2kg= 3m/s2distance travelled in 4 second= 24 mWORK DONE BY APPLIED NET FORCE= 6N X 24m=144J
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