a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

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JITENDRA KUMAR · Answer

friction force= 4N APPLIED FORCE= 10 N NET FORCE= 10N-4N= 6N acceleration of block= 6N/2kg= 3m/s2 distance travelled in 4 second= 24 m WORK DONE BY APPLIED NET FORCE= 6N X 24m=144J

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a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

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a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

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