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Grade:

                        

a block of mass 2 kg is resting on a horizontal table . A force of 10N is applied for 4 sec on the block in the horizontal direction . If g = 10 m/s² and the coefficient of kinetic friction between the block and the table = 0.2, then the work done by the net force is ?

2 years ago

Answers : (1)

JITENDRA KUMAR
15 Points
							
friction force= 4N
APPLIED FORCE= 10 N
NET FORCE= 10N-4N= 6N
acceleration of block= 6N/2kg= 3m/s2
distance travelled in 4 second= 24 m
WORK DONE BY APPLIED NET FORCE= 6N X 24m=144J
2 years ago
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