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Grade: 11
        
A block of mass 15 kgis placed on inclined plane when an angel of inclination is 30 the block just begin to slide the plane what is the sliding fricition
one month ago

Answers : (2)

Arun
21514 Points
							
 
first of all 1 kg.wt means a force that is required to accelerate a mass of 15 kg with an acceleration of approx 9.8 m/s2.
here the block is just going to slide down the wedge..so friction force needed to stop the block is mg*sin30.
since, mass  = 15kg, force required  = 15*g*sin30 newton
= 7.5*g  newton
= 7.5 kg.wt …............... {since 1 kg.wt = 1*g newton, where g = 9.8 m/s2 }
one month ago
Khimraj
2905 Points
							

In equilibrium,

F=mg sin 30°…………(1)

R=mg cos 30°…………(2)

On dividing ( 1) by (2), we get

F/R= mg sin 30°/mg cos 30°

or, friction coefficient= tan 30°.

one month ago
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