Grade 11Mechanics

A block of mass 15 kgis placed on inclined plane when an angel of inclination is 30 the block just begin to slide the plane what is the sliding fricition

Kunal

7 Years agoGrade 11

2 Answers

Arun

7 Years ago

first of all 1 kg.wt means a force that is required to accelerate a mass of 15 kg with an acceleration of approx 9.8 m/s2.

here the block is just going to slide down the wedge..so friction force needed to stop the block is mg*sin30.

since, mass = 15kg, force required = 15*g*sin30 newton

= 7.5*g newton

= 7.5 kg.wt …............... {since 1 kg.wt = 1*g newton, where g = 9.8 m/s2 }

Khimraj

7 Years ago

In equilibrium,

F=mg sin 30°…………(1)

R=mg cos 30°…………(2)

On dividing ( 1) by (2), we get

F/R= mg sin 30°/mg cos 30°

or, friction coefficient= tan 30°.

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A block of mass 15 kgis placed on inclined plane when an angel of inclination is 30 the block just begin to slide the plane what is the sliding fricition

Kunal

2 Answers

Arun

Khimraj

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