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Grade: 11
A block of mass 15 kgis placed on inclined plane when an angel of inclination is 30 the block just begin to slide the plane what is the sliding fricition
one year ago

Answers : (2)

24740 Points
first of all 1 kg.wt means a force that is required to accelerate a mass of 15 kg with an acceleration of approx 9.8 m/s2.
here the block is just going to slide down the friction force needed to stop the block is mg*sin30.
since, mass  = 15kg, force required  = 15*g*sin30 newton
= 7.5*g  newton
= 7.5 kg.wt …............... {since 1 kg.wt = 1*g newton, where g = 9.8 m/s2 }
one year ago
3007 Points

In equilibrium,

F=mg sin 30°…………(1)

R=mg cos 30°…………(2)

On dividing ( 1) by (2), we get

F/R= mg sin 30°/mg cos 30°

or, friction coefficient= tan 30°.

one year ago
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