A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

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Arun · Answer

Using the conservation of energy mgh=1/2 mv ²+ 12 given mass =1.5Kg velocity=8m/s 1.5*10*h=1/2*1.5*8 ²+12 15h=60 h=4m so the radius also should be equal to 4m

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A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

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A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

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