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# A block of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontal position in reaching to the bottom its velocity is 8 M per second the work done is overcoming the friction is 12j the radius of circle is

2 years ago

Arun
25768 Points

Using the conservation of energy

mgh=1/2 mv
²+ 12

given mass =1.5Kg

velocity=8m/s

1.5*10*h=1/2*1.5*8
²+12

15h=60

h=4m

so the radius also should be equal to 4m
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions