MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
A block of mass 0.1kg is held against a wall by applying horizontal force of 5N on the block.if the coefficient of friction of the block and wall is 0.5 then the magnitude of the frictional force acting on the block is?
one year ago

Answers : (2)

Arun
22820 Points
							
Dear student
 
Since the block is held against a wall, the coefficient of friction will be equal to the weight of the block.
 
Hence
mu = m*g = 0.1 *9.8 = 0.98 N
one year ago
Disha Sharma
18 Points
							
The frictional force will be directed upwards as shown as gravity will be assisting its motion and the frictional force will be due to 5 N force normal to the block towards the wall.
Hence max. static frictional force: F = 0.5 x 5 = 2.5 N
FOrce due to mass of block= mg = 0.1 x 10 = 1 N
Since it is less than max static frictional force hence frictional force on the block will be 1 N
4 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details