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Grade: 12
A block of mass 0.1kg is held against a wall by applying horizontal force of 5N on the block.if the coefficient of friction of the block and wall is 0.5 then the magnitude of the frictional force acting on the block is?
one year ago

Answers : (2)

22820 Points
Dear student
Since the block is held against a wall, the coefficient of friction will be equal to the weight of the block.
mu = m*g = 0.1 *9.8 = 0.98 N
one year ago
Disha Sharma
18 Points
The frictional force will be directed upwards as shown as gravity will be assisting its motion and the frictional force will be due to 5 N force normal to the block towards the wall.
Hence max. static frictional force: F = 0.5 x 5 = 2.5 N
FOrce due to mass of block= mg = 0.1 x 10 = 1 N
Since it is less than max static frictional force hence frictional force on the block will be 1 N
4 months ago
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