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A block of 100N is slowly slid up on a smooth incline of inclination 37 degree by a person .calculate the work done by the person in moving the block through a dostqnce of 2m,if the driving force is (a)parallel to the incline (b) in the horizontal direction.
Firstly we resolve the components of weight along the inclined and perpendicular to the inclined. (a) parallel to the inclined component will be mgsin37°=100×(3÷5) {sin37°=3÷5} =60 work done=force ×displacement =60×2=120j similarly in horizontal direction mgcos37°=80{cos37°=4÷5} work done =force ×displacement =80×2=160j
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