A block of 100N is slowly slid up on a smooth incline of inclination 37 degree by a person .calculate the work done by the person in moving the block through a dostqnce of 2m,if the driving force is (a)parallel to the incline (b) in the horizontal direction.

Question

Deepak · Answer

Firstly we resolve the components of weight along the inclined and perpendicular to the inclined. (a) parallel to the inclined component will be mgsin37°=100×(3÷5) {sin37°=3÷5} =60 work done=force ×displacement =60×2=120j similarly in horizontal direction mgcos37°=80{cos37°=4÷5} work done =force ×displacement =80×2=160j

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

A block of 100N is slowly slid up on a smooth incline of inclination 37 degree by a person .calculate the work done by the person in moving the block through a dostqnce of 2m,if the driving force is (a)parallel to the incline (b) in the horizontal direction.

A block of 100N is slowly slid up on a smooth incline of inclination 37 degree by a person .calculate the work done by the person in moving the block through a dostqnce of 2m,if the driving force is (a)parallel to the incline (b) in the horizontal direction.

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship