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a block is resting on a plane inclined at 22 degree.a force of 235N acts at 60 degree on the block.determine its parallel and perpendicular components.

Krishna Mangalampalli , 8 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Along the inclined and perpendcular the forces after doing components of 235 N we get :
Along the plane(parallely) => Fcos60cos22+ Fsin60cos68 + mgsin22 => 235*0.927/2 + 0.374*1.73*235/2=> 184.944 N
and
Perpendicular the plane => Fcos60sin22 + Fsin60sin68 + mgcos22 => 0.347*235/2 +  0.374*1.73*235/2 => 116.79 N
 

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