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`        A block is kept on the floor of an elevator at reat.The elevator start decending with an accelerationOf 12m/sec2.Find the displacement of the block during the first 0.2 second after the start. Take g=10m/sec2`
3 months ago

Khimraj
3008 Points
```							Since the acceleration of elevator is greater than g (Acceleration due to gravity 9.8 m/s2 ) and block and elevator are not attached, the block will get separated and move like free fall body with acceleration g. we know s=ut+1/2at^2 where u=0 and a=g(free falll acceleration) s=1/2 * 10* 0.2^2...
```
3 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions